Answer:
a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.
b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.
Step-by-step explanation:
Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.
To find : What is the probability that
(a) the total gross sales over the next 2 weeks exceeds $5000;
(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?
Solution :
Let and denote the sales during week 1 and 2 respectively.
a) Let
Assuming that and follows same distribution with same mean and deviation.
So,
The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.
b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.
We use binomial distribution with n=3.
Let Y be the number of weeks in which sales exceed 2000.
Now,
So,
The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.
Answer:
×+2 ×^3=4×6^7÷5=^43×2
Step-by-step explanation:
43×2÷34=45×
Step-by-step explanation:
1 l = 22.5 km
125 l = 22.5 × 125 = 2812.5 km
Okay, so first you draw a picture and let x be the distance from point D to the rest stop. Then the distance from point to the rest stop is 8 - x
You know that the length of the new trail is y + z, where y is the distance from Ancaster to the rest stop and z is the distance from Dundas to the rest stop.
Now by the Pythagorean theorem, y^2 = 4^2 + x^2 and z^2 = 6^2 + (8 - x) ^2
So take square roots of these, add them, and minimize.
Note: I am assuming the path is perfectly straight, otherwise this approach fails.
The answer is either C or D hope that helped a little