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2 years ago

5

1/5 subtracted by 1/10 fractions

2 answers:

jeka942 years ago

5 0

The answer that i got was 1/10

Aleks04 [339]2 years ago

4 0

Make the bottom number the same!
=2/10-1/10
final answer =1/10

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Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?

Eddi Din [679]

Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

$|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }$

The magnitude of vecor v is given to be 10. So we can write:

$10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}$

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.

The point in option d, satisfies the equation.

$100=(-1+7)^{2} +(5+3)^{2} \\ \\ 
100=36+64 \\ \\ 
100=100$

Thus, the answer to this question is option D

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%3Cbr%3E%0Ay%3D%20x%5E%7B2%7D%20-9" id="TexFormula1" title="&#10;y= x^{2} -9" alt="&#1

svp [43]

Simple...

y= $x^{2} -9$

$y= x^{2} -9$

It's quite easy to see $x^{2} = x^{2}$

Thus, any value of x makes the equation true.

Thus, your answer.

7 0

2 years ago

Please help with this fast

Elena-2011 [213]

Answer:

Part 1) The value of x is 50°

Part 2) The measure of angle LOK is 114°

Option C

Step-by-step explanation:

we know that

if two angles are supplementary, then their sum is equal to 180 degrees

so

(x+64)°+66°=180°

solve for x

x+130°=180°

x=180°-130°=50°

Find the measure of angle LOK

∠LOK=(x+64)°

∠LOK=(50+64)°=114°

4 0

2 years ago

Which inequalities are true? Check all that apply. Three-fifths < 0 Four-sixths greater-than one-half Nine-elevenths < 1 T

Kipish [7]

$\frac{3}{5} < 0$

$\frac{8}{16} > \frac{1}{2}\\\\$

<em><u>Solution:</u></em>

<em><u>We have to find the inequalities that are true</u></em>

<em><u>Option 1</u></em>

$\frac{3}{5} < 0\\\\0.6 < 0$

0.6 is not less than 0

Thus this inequality is not true

<em><u>Option 2</u></em>

$\frac{4}{6} > \frac{1}{2}\\\\0.667 > 0.5$

0.667 is greater than 0.5

Thus this inequality is true

<em><u>Option 3</u></em>

$\frac{9}{11} < 1\\\\0.818 < 1$

0.818 is less than 1

Thus this inequality is true

<em><u>Option 4</u></em>

$\frac{8}{16} > \frac{1}{2}\\\\$

0.5 = 0.5

Thus the above inequality is not true

6 0

2 years ago

Divide this polynomial:)

lutik1710 [3]

Answer:

The answer is 3x^2-4x-4+1/2x-1

Step-by-step explanation:

Hope this helps, and sorry if it's wrong.

8 0

2 years ago

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