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3 years ago

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Aiden estimates that the length of a piece of rope is 8.5 inches. If its actual length is 7.1 inches, what is the percent error

of Aiden’s estimate? Round to the nearest tenth if necessary. *

1 answer:

AlexFokin [52]3 years ago

4 0

The correct answer is 16.5%

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Simplify the expression (12x^2y^-2)^5 (4xy^-3)^-7

riadik2000 [5.3K]

(12x^2y^−2)^5(4xy^-3)^−7 = (248832x^10y^21)/(16384x^7y^10) = (248832x^3y^11)/(16384) = (243x^3y^11)/16

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3 years ago

Can someone help me please please please

marissa [1.9K]

Use the Pythagorean theorem $a^{2} + b^{2} = c^{2}$ to find the missing side length of a right triangle

In this case, after you plug in the given numbers your equation is $12^{2} + y^{2} = 20^{2}$

Then, Just solve that equation for y.

$144 + y^{2} = 400$

$x^{2} = 256$

$\sqrt{} y^{2} = \sqrt{256}$

y = 16

So the answer is B, 16 cm.

I hope this helps, please feel free to ask questions if you're still confused :)

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3 years ago

What is the proportional relationship represented by this table?

77julia77 [94]

Answer:

the constant of proportionality is 0.2 and it is a proportional relationship

Step-by-step explanation:

2 divided by 10 is 0.2

1 divided by 5 is 0.2

they have the same answer so they are proportional

since they have the answer 0.2 it

is there constant of proportionality

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3 years ago

Solve the following equation : 6x =12

densk [106]

X=2 here very simple

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3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago