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Alika [10]
3 years ago
12

What is the solution to the system of equations?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

d

Step-by-step explanation:

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Evaluate n+2x2 when n=3 and x=−2.
krok68 [10]

Answer:

When n=3 and x=−2  the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

p (n,x) = n + 2x^{2}

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

p (n,x) = n + 2x^{2}

Substituting n = 3 and x = -2 we get

p (3, -2) = 3 + 2(-2)^{2}

Negative square gives positive number therefore (-2)²=4

p (3, -2) = 3 + 2\times 4

p (3, -2) = 3 + 8\\p (3, -2) = 11

When n=3 and x=−2  the answer is 11.

7 0
3 years ago
Round 3.5555 to the nearest thousandth
Dmitriy789 [7]
3.556 is the correct answer
4 0
3 years ago
Read 2 more answers
HI! please help out ASAP this is due today! Explain it the best you can and send a picture explaining it so I won’t get confused
Arte-miy333 [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
Evaluate the expression when g=3 and h= 17 <br> h−5g
Aleks04 [339]
2.
EXPLANATION:
If g= 3 we can replace g with 3.

Now we have h-5 x 3

and if h= 17, we can replace h with 17.

Now we have 17 - 5 x 3.

because of pemdas, multiplication is first

5 x 3 is 15,

17 - 15 is 2.

2.


5 0
3 years ago
Read 2 more answers
Use Gauss's approach to find the following sums (do not use formulas) a 1+2+3+4 998 b. 1+3+5 7+ 1001 a The sum of the sequence i
valkas [14]

Answer:

(a) 498501

(b) 251001

Step-by-step explanation:

According Gauss's approach, the sum of a series is

sum=\frac{n(a_1+a_n)}{2}         .... (1)

where, n is number of terms.

(a)

The given series is

1+2+3+4+...+998

here,

a_1=1

a_n=998

n=998

Substitute a_1=1, a_n=998 and n=998 in equation (1).

sum=\frac{998(1+998)}{2}

sum=499(999)

sum=498501

Therefore the sum of series is 498501.

(b)

The given series is

1+3+5+7+...+ 1001

The given series is the sum of dd natural numbers.

In 1001 natural numbers 500 are even numbers and 501 are odd number because alternative numbers are even.

a_1=1

a_n=1001

n=501

Substitute a_1=1, a_n=1001 and n=501 in equation (1).

sum=\frac{501(1+1001)}{2}

sum=\frac{501(1002)}{2}

sum=501(501)

sum=251001

Therefore the sum of series is 251001.

8 0
3 years ago
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