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2 years ago

Please help me i'll give 20 points to whoever helps me answer all 4 of them and brainly

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

7 0

Answer:

G - number of arrangements

F. the amount of her allowance

B. y = x

H. the number of hours

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Find the angle (picture included)

vodka [1.7K]

Answer:14

Step-by-step explanation:

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3 years ago

PLZZ HELP ANSWER FIRST YOU GET 22 POINTS AND BRAINLYEST AND THERE IS A PICTURE

Svetllana [295]

2nd one 5n= -25 and +13 negative 25 is n^2

4 0

3 years ago

Read 2 more answers

Point N lies on the line segment MP . The distance between points M and P is 24 cm, and the distance between points N and M is t

Katarina [22]

Answer:

(a)The distance between points N and P is 8 cm.

(b)The distance between points M and N is 16 cm.

Step-by-step explanation:

Given that,

Point N lies on the line segment MP.

The distance between M and P is 24 cm.

That is MP= 24 cm

The distance between points N and M is twice longer than between points N and P.

That is

MN = 2 NP.

Since the point N lies on the line segment MP.

So, MN+NP= MP.

∴2 NP + NP= 24 [∵ MP= 24 cm]

⇒3 NP= 24

$\Rightarrow NP= \frac{24}{3}$

⇒NP= 8

The distance between points N and P is 8 cm.

(b)

Since

MN= 2 NP

⇒MN= 2×8

⇒MN= 16 cm.

The distance between points M and N is 16 cm.

7 0

2 years ago

Pls guys help me pls

galina1969 [7]

Answer:

$x < 5$

I think the answer is A

8 0

2 years ago

How do you integrate arctan(x dx? i think that if you simplify the integral you get:?

Temka [501]

Integration by parts will help here. Letting $u=\arctan x$ and $\mathrm dv=\mathrm dx$ , you end up with $\mathrm du=\dfrac{\mathrm dx}{1+x^2}$ and $v=x$ . Now

$\displaystyle\int\arctan x\,\mathrm dx=uv-\int v\,\mathrm du$
$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\int\frac x{1+x^2}\,\mathrm dx$

For the remaining integral, setting $y=1+x^2$ gives $\dfrac{\mathrm dy}2=x\,\mathrm dx$ , so

$\displaystyle\int\frac x{1+x^2}\,\mathrm dx=\frac12\int\frac{\mathrm dy}y=\frac12\ln|y|+C=\frac12\ln(1+x^2)+C$

Putting everything together, you end up with

$\displaystyle\int\arctan x\,\mathrm dx=x\arctan x-\frac12\ln(1+x^2)+C$

6 0

2 years ago