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3 years ago

15

What values of c makes the polynomial below a perfect square?

1 answer:

sweet [91]3 years ago

8 0

To find the perfect square of an equation, you just take your "middle" term (in this case, 16), divide it by 2, then square it.

16/2 = 8
8^2 = 64

your perfect square is 64. you can check it really quick by trying to factor x^2 + 16x + 64 and seeing that it breaks down perfectly into (x + 8)(x + 8), which can be written as (x + 8)^2, showing that you have a binomial with a perfect square!!

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PLEASE SOMEONE HELP ME. I WILL BRAINLIEST YOU AND GIVE YOU POINTS.

almond37 [142]

Answer:

C).

Step-by-step explanation:

-3x+2 and[(-)(x^2+5x)

3x+2 and (-x^2+5x)

3x+2-x^2+5x

-x^2-8x+2

Hope this Helps :)

7 0

3 years ago

Elan Coil [88]

Answer:

b.

Step-by-step explanation:

6 0

3 years ago

The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr

Kobotan [32]

Answer:

% change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

$T = 2.5 x + 0.5 x^{2}$

We will approximate this distance using the relation

$f (x + dx) = f (x)+ f' (x)dx$

dx = 26 - 25 = 1

T' = 2.5 + x

Therefore

$f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x$

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× $25^{2}$ + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × $25^{2}$

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

% change in stopping distance = $\frac{27.5}{375}$ × 100

% change in stopping distance = 7.34 %

6 0

3 years ago

Paisley's car used 11 gallons to travel 374 miles. How many gallons of gas would she need to travel 442 miles?

katen-ka-za [31]

Answer:

13 gallons

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find magnitude and directionof vector a = ( -3 , -3 )

nevsk [136]

Answer:

Step-by-step explanation:

Magnitude: |a|= $\sqrt{(-3)^{2}+(-3)^{2} }=3\sqrt{2}$

Direction: in the negative direction of the Ox axe and Oy axe

3 0

2 years ago