The y intercept is where m=0. Hence, set m=0 and solve for c:
c=0.05(0)+4.95
c=4.95
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
My day was good lol thanks for askinggg
