Answer:
6500 lb
Step-by-step explanation:
The load limit of the bridge is ...
(5000 kg)(2.2 lb/kg) = 11,000 lb
The total of truck and trailer cannot exceed this value, so the trailer's weight cannot exceed ...
11,000 lb -4,500 lb = 6,500 lb . . . max trailer weight
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
AA
Step-by-step explanation:
Answer:
Approximately 0.333
Step-by-step explanation:
If we graph this we see that the line goes over the y-axis at (0,0.333)
*I use desmos graphing calculator*
