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3 years ago

Write a polynomial with roots r1 and r2 if 1. R1 + r2=4 2. R1 x r2=4

Mathematics

1 answer:

KiRa [710]3 years ago

6 0

Answer:

r²- 4r + 4

Step-by-step explanation:

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john and jack found a coin on the sidewalk. they argued about whether the coin is fair. john claimed a 40% chance for the coin t

expeople1 [14]

Since it is observed that I z I = 3.464 > 1.96 it is concluded that the null hypothesis is rejected.

Therefore we reject John's claim.

Here:

we can use 1 sample proportion test to check the claim of John

H₀ : p₀ = 0.4

H₁ : p₀ ≠ 0.4

Test statistic is

z = p - p₀/√p₀(1-p₀)n

Let X be the random variable denoting the number of heads.

Now p = X/n

= 8/50

= 0.16

p₀ = 0.4

1-p₀ = 1-0.4

= 0.6

z = -3.464

since it is observed that I z I = 3.464 > 1.96 it is concluded that the null hypothesis is rejected.

Therefore we reject John's claim.

Learn more about Null hypothesis here:

brainly.com/question/15980493

#SPJ4

6 0

1 year ago

Maths a²(5a - 3b) -3a²

11Alexandr11 [23.1K]

Answer:

$5a^{3} - 3a^{2} b-3a^{2}$

Step-by-step explanation:

$a^{2} (5a-3b)-3a^{2} |$

Expand brackets

$5a^{3} - 3a^{2} b-3a^{2}$

Final Answer is

$5a^{3} - 3a^{2} b-3a^{2}$

4 0

2 years ago

Select all that apply.

julsineya [31]

Answer:

The first and third is correct.

Step-by-step explanation:

I'm not a expert but I know its right.

6 0

3 years ago

Read 2 more answers

I’m stuck I need help

arlik [135]

Answer:

X=6

Step-by-step explanation:

First step isolate the variable;2x=12

Simplify;x=12/2=6

8 0

3 years ago

suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

4 years ago