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anygoal [31]
3 years ago
12

349 times 3 expanded form

Mathematics
1 answer:
kozerog [31]3 years ago
7 0

Answer:

1000 + 40 + 7

Step-by-step explanation:

MULTIPLY:

349 times 3 = 1,047

EXPANDED FORM:

1000 + 40 + 7

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#14 pls! Help me please y’all
dsp73

Answer: The Answer is 7, Hope this helps! :)

Step-by-step explanation: We know that 6 and 12 are related, 6 times 2 is 12 so if you do the same for 4 and you multiply 4 by 2 you get 8 for the blank side, then subtract 1 from 8 to get 7. Same for the bigger triangle, 6 times 2 is 12 subtracted by 1 is 11.

So final answer is 7 for X!

4 0
3 years ago
Am I right or wrong?
omeli [17]

You are absolutely right.

8 0
3 years ago
Marle placed two orders at the same restaurant last month. In one order, she received 5 trays of lasagna and 3 trays of
user100 [1]

Answer:

$25.25-lasagna, $12.25-garlic bread

Step-by-step explanation:

  5L+3G=163

- 4L+4G=150

______________

 4(5L+3G=163)

-5(4L+4G=150)

_____________

20L+12G=652

-20L-20G=-750

_____________

          -8G=-98

         -8G/-8 = -98/-8

               G=$12.25

now plug that into G in any of the 2 equations at the top and you can solve for L(price of lasagna)

5 0
3 years ago
A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
3 years ago
Five friends Al, Bet, Cat, Don, and Ella live on the island where everyone is either a knight or a knave
nalin [4]

Answer:

?

Step-by-step explanation:

what am i tryign to solve here

8 0
3 years ago
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