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2 years ago

What is the solution set for −4 x + 10 ≥ 5 x + 55?

Mathematics

1 answer:

valentina_108 [34]2 years ago

8 0

Answer:

(-5,0)

Step-by-step explanation:

Put -4x+10 ≥ 5x+55 in Desmos Scientific Calculator and you have your answer

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What is the solution set for

Mumz [18]

Answer: C. (-3, 9)

Step-by-step explanation:

Given

2|x-3|=12

Divide both sides by 2

2|x-3|/2=12/2

|x-3|=6

Take of absolute value sign (REMEMBER need to take into consideration of two conditions)

x-3=±6

1)x-3=6

x=9

2)x-3=-6

x=-3

**NOTE**: need to check each solution whether or not they are suitable

Hope this helps!! :)

Please let me know if you have any questions

5 0

2 years ago

Camison's minnan gets 14 miles per gallon for city driving and 19 miles per gan

loris [4]

Answer:

7 gallons were used for city driving and 17 gallons were used for highway driving

Correct statement and question:

camison's minnan gets 14 miles per gallon for city driving and 19 miles per gallon for highway driving. At the beginning of the week, the 24-gallon tank was full. The family traveled 421 miles before running out of gas. How many gallons were used for city driving and how many were used for highway driving?

Source:

Previous question found at brainly

Step-by-step explanation:

x = Gallons for city driving

24 - x = Gallons for highway driving

Miles drove before running out of gas = 421

Now let's solve for x, writing the following equation:

14x + 19 (24 - x) = 421

14x + 456 - 19x = 421

-5x = 421 - 456

-5x = - 35

x = -35/-5

x = 7 ⇒ 24 -x = 17

7 gallons were used for city driving and 17 gallons were used for highway driving

3 0

2 years ago

Solve this rational equation <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx%20%2B%204%7D%20%20%3D%20%20%5Cfrac%7B4%7

sergey [27]

Answer:

$x = - 12$

C.E.: x =/= -4

Step-by-step explanation:

$\frac{x}{x + 4} = \frac{4}{x + 4} + 2 \\ \frac{x}{x + 4} = \frac{4 + 2x + 8}{x + 4} \\ x = 4 + 2x + 8 \\ - x = 12 \\ x = - 12$

6 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

Estimate the quotients 3.53/51 =

ale4655 [162]

An accurate estimate is anywhere from 0.06 to 0.07. The exact answer is 0.06921568627.

3 0

3 years ago