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Elena L [17]
3 years ago
13

A recent survey found that 80% of jeans have back pockets, 65% have front pockets, and 48% have both back and

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

.52

Step-by-step explanation:

its only a little bit over a 50% chance to get a front pocketed jean, then to also have back pockets is under 50% chance so when you even those it comes to .52

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Step-by-step explanation:

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Please help this is already late ​
GaryK [48]

Answer:

C = 132°

Step-by-step explanation:

(5y + 28) = 12y

5y - 5y + 28 = 12y - 5y

28 = 7y

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12 (4)

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C = 132°

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Billy watched the clown car drive up to the circus and saw
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14%=56%
56%=56/100=0.56

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Choose the correct problem formulation: Hotels, like airlines, often overbook, counting on the fact that some people with reserv
Marina CMI [18]

Answer:

P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)

P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429

P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032

P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878

P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501

P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=15, p=1-0.2=0.8)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(8 < x \leq 12)=P(X=9)+P(X=10)+P(X=11)+P(X=12)

P(X=9)=(15C9)(0.8)^{9} (1-0.8)^{15-9}=0.0429

P(X=10)=(15C10)(0.8)^{10} (1-0.8)^{15-10}=0.1032

P(X=11)=(15C11)(0.8)^{11} (1-0.8)^{15-11}=0.1878

P(X=12)=(15C12)(0.8)^{12} (1-0.8)^{15-12}=0.2501

P(8 < x \leq 12)=0.0429+0.1032+0.1878 +0.2501=0.5839

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Reflection over the y-axis of the point (9,-1)(9,−1)
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The new point is (9,1)
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