Answer:
what solid??????
Step-by-step explanation:
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+
x=(-1)
Let x=0
y+
x=(-1)
y+
(0)=(-1)
y=(-1)
Let x=2
y+
x=(-1)
y+
(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
Answer:
54
Step-by-step explanation:
BEDMAS
z=10
(10)3-3(2-10)
=(10)3-3(-8)
=30-(-24) *2 negatives = a positive
=30+24
=54
20
the input value in the x column is multiplied by 5 to get the output value in the y column
Answer:
77.2°
Step-by-step explanation:
Consider the triangle JKR.
∠KJR=108.6 (lies on the same line as ∠RJA, angles on a straight line add up to 180)
All the angles in a triangle add up to 180, so:
∠JKR+∠KJR+∠JRK=180
∠JKR+108.6+32.8=180
∠JKR=38.6=∠RKA
Consider ∠RKA. This angle stands on the same arc as ∠RCA.
Since the angle at centre is twice the angle at circumference, 2(∠RKA) = ∠RCA.
2(∠RKA) = ∠RCA
2(38.6)=∠RCA
∠RCA=77.2°