All categories

2 years ago

Is, “What is your favorite color?” A statistical question? Why or why not?

Mathematics

1 answer:

nignag [31]2 years ago

4 0

Answer:

This is a statistical question because to answer this question, you would collect data by asking students about their favorite colors, and there would be variability in the data. The favorite color would not be the same for every student

Step-by-step explanation:

You might be interested in

MATHEMATICS Matemáticas

expeople1 [14]

18. and 3 divided is 06

5 0

2 years ago

What is the number of ways to arrange 6 objects from a set of 10 different objects

bagirrra123 [75]

<span>10!/(10-6)! =
3628800/24 =
151200
</span> So the answer is 151200

6 0

3 years ago

Read 2 more answers

Determine whether the triangles are similar, if so what is a similarity statement in the postulate or theorem used?

alexandr1967 [171]

Answer:

It is the secon option ∆TRS ≈ ∆TPQ ; SAS

Step-by-step explanation: angle t is equal to angle t because it is the same angle

line TR divided by line TP is equal to line TS divided by TQ

3 0

2 years ago

Read 2 more answers

Which set of angles could be the interior angles of a triangle?

Minchanka [31]

Answer:

D. 20°, 60°, and 100°

Step-by-step explanation:

basically you're testing which set adds up to 180°:

D should immediately catch the eye since it has a simple 100°, and 60+20 is 80, making D the correct answer

a: 189°

b: 90°

c: 120°

d: 180°

7 0

2 years ago

HELP!! Algebra help!! Will give stars thank u so much <333

Anna35 [415]

Answers:

Part a) $\bf{\sqrt{x^2+(x^2-3)^2}$
Part b) 3
Part c) 2.24
Part d) 1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

$d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\$

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying $d = \sqrt{x^2 + (x^2-3)^2}$ is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\$

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

$d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\$

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0

2 years ago