So i think what you do is if you make a number line like this:
1...2...3...4...5...6...7...8
you have to find out how many numbers are in between 4 and 7, so I would be 3 because there are 3 numbers I between 4-7.
so
a) 3
b) 6
c) 14
d) 8
Answer:
B and C
(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e
Answer:
12
Step-by-step explanation:
4 x 3 is 12
Answer:
B. -10 its a negative number
For systems of equations try using graphing, substitution, and elimination. For example
{2x+7y=3}
{x=-4y}
You should first look at if you have a variable that can be substituted (using substitution) and in this case we do! you plug in the x into 2x meaning 2(-4y)+7y=3
1) distribute -8y+7y=3
2) combine like terms in this case -8y+7y= -1y
3) solve -1y=3
y=-3
so currently our solution is (0,-3)
now we solve for x.
we plug our solved variable (y) into 7y
7(-3) and our equation looks like this
2x+7(-3)=3
1) distribute 7(-3)=-21
2) rewrite then solve 2x+(-21)=3
3) isolate variable -21+21 & 3+21
4) 2x=24
5) solve 2/24 = 12
Meaning our solution is (12,-3)
This is how to solve by substitution.
