Y = 6x
4x + y = 7
(substitute y = 6x in the ‘y’ spot in 4x + y = 7)
4x + 6x = 7
10x = 7
/10 on both sides
x = 7/10
(substitute x = 7/10 in the ‘x’ spot in either of the two equations)
y = 6x
y = 6(7/10)
y = 4.2 = 21/5
Answer:
x = 7/10
y = 21/5
The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Given that,
y forms a circle of radius r
y=2r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum = r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4 + 2(y-2)/16 =0
y/2 + (y-2)/8 =0
y = 2/+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/+4
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Answer:
D. difference of squares
Step-by-step explanation:
Both of the terms x^2 and 9 are squares, so their difference is the difference of squares. The factorization of that is a "special form" that can be usefully memorized.
a^2 -b^2 = (a -b)(a +b)
x^2 -9 = (x -3)(x +3)
Answer:
1. X > 8
2. a. X < 5
Step-by-step explanation:
1. 3x - 8 > 16
+8. +8
3x > 24
divide both sides by 3
x >8
2. 2x - 1 < 9
+1. +1
2x < 10
divide both sides by 2
x < 5
