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Alex Ar [27]
3 years ago
14

Use the diagram to solve for x 15x + 5 16x+2

Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

3

Step-by-step explanation:

I think you set them equal to each other.so you would do 16x+2=15x+5 and you would get x=3. I hope this helps out! ☺️

ipn [44]3 years ago
5 0
15x+5= 5(3x+1)
16x+2= 2(8x+1)
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Elodia [21]

Answer:

KO,ML,MP

Step-by-step explanation:

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6 0
2 years ago
Sandra has a rectangular pool in her backyard that is 9 feet long and 4 feet wide. A resort has a pool that is similar in shape,
SpyIntel [72]

Answer:

Length of the resort pool is 13.5 ft.

Step-by-step explanation:

Since, both the rectangular pools are similar in shape,

Corresponding sides of these pools will be proportional.

By the property of similarity,

\frac{\text{Length of resort pool}}{\text{Length of backyard pool}}= \frac{\text{Width of the resort pool}}{\text{Width of the backyard pool}}

\frac{l}{9}=\frac{6}{4}

l = \frac{6\times 9}{4}

l = 13.5 ft

Therefore, length of the resort pool will be 13.5 ft.

3 0
3 years ago
16a3b7 + 2a6b4 − 22a4b5.
natima [27]

Answer:

-4a5b2 is your answer.

6 0
3 years ago
A circle is centered about the point (2, 0). The point (0, 1) is on the circle. Which statement proves that the point (4, 1) is
mestny [16]

Answer:

Step-by-step explanation:

the circle is at the origin and (0,4) is a point on the circle then the radius of the circle is:

r^2=0^2+4^2

r^2=16

r=4

so we can check that the other point is four units from the origin and thus also on the circle...

d^2=2^2+6^2

d^2=4+36

d^2=40

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8 0
3 years ago
The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal
Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The other parameters are given as follows:

\overline{x} = 111000, \sigma = 36730, n = 36

Hence, the lower bound of the interval is:

\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
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