Answer:
10^20
Step-by-step explanation:
So in this word problem, we have to multiply 10^13 bacteria cells on a single person by the 10^7 of people.
Always remember this, when you have exponenets with the same bases, and the question asks for multiplying and dividing exponents, you just need to add and subtract the exponent.
So in this case, we will just add since it calls for multipactation.
So we need to solve:
10^13+7
This will just equal:
<u>10^20 power</u>
Hope this helps ;)
The roots of the quadratic equation
are
.
Here the given quadratic equation is
. Here
.
The roots are
![x=\frac{13 \pm \sqrt{13^2-4*5*7}}{2*5} \\ x=\frac{13 \pm \sqrt{29}}{10}](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B13%20%5Cpm%20%5Csqrt%7B13%5E2-4%2A5%2A7%7D%7D%7B2%2A5%7D%20%5C%5C%20x%3D%5Cfrac%7B13%20%5Cpm%20%5Csqrt%7B29%7D%7D%7B10%7D%20%20%20)
Since it is positive power, the answer is -1 so it is B.
Answer:
The correct answer is 1/49
Step-by-step explanation:
In order to find this, we first can eliminate the negative in the exponent by putting the whole this in the denominator.
(-7)^-2 = 1/(-7)^2
Now we can evaluate the denominator
1/(-7)^2 = 1/49
Answer:
2010.
Step-by-step explanation:
We have been given an exponential growth formula
, which represents number of passengers traveling by airplane since 1990.
To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:
![900=466\cdot 1.035^t](https://tex.z-dn.net/?f=900%3D466%5Ccdot%201.035%5Et)
![\frac{900}{466}=\frac{466\cdot 1.035^t}{466}](https://tex.z-dn.net/?f=%5Cfrac%7B900%7D%7B466%7D%3D%5Cfrac%7B466%5Ccdot%201.035%5Et%7D%7B466%7D)
![1.9313304721030043=1.035^t](https://tex.z-dn.net/?f=1.9313304721030043%3D1.035%5Et)
Take natural log of both sides:
![\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)](https://tex.z-dn.net/?f=%5Ctext%7Bln%7D%281.9313304721030043%29%3D%5Ctext%7Bln%7D%281.035%5Et%29)
Using property
, we will get:
![\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)](https://tex.z-dn.net/?f=%5Ctext%7Bln%7D%281.9313304721030043%29%3Dt%5Ccdot%20%5Ctext%7Bln%7D%281.035%29)
![0.658209129198=t\cdot 0.034401426717](https://tex.z-dn.net/?f=0.658209129198%3Dt%5Ccdot%200.034401426717)
![\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}](https://tex.z-dn.net/?f=%5Cfrac%7B0.658209129198%7D%7B0.034401426717%7D%3D%5Cfrac%7Bt%5Ccdot%200.034401426717%7D%7B0.034401426717%7D)
![19.1331927775=t\\\\t=19.1331927775](https://tex.z-dn.net/?f=19.1331927775%3Dt%5C%5C%5C%5Ct%3D19.1331927775)
This means that in the 20th year since 1990, 900 million passengers would travel by airline.
![1990+20=2010](https://tex.z-dn.net/?f=1990%2B20%3D2010)
Therefore, 900 million passengers would travel by airline in 2010.