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Vladimir79 [104]
3 years ago
5

Paola subtracts 9,405 from 11,038 Should Paola's answer be greater or les than 2,000? explain

Mathematics
1 answer:
matrenka [14]3 years ago
4 0
It should be less then 2000 even though 11000-9000=2000 there are the ends, the thousands place should not be the only thing you should worry about
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mrs. robinson bought a novel at bookstore on sale for 20% off its regular price of $ 29.99.mr. chang bougth the same novel at a
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29.99-20%= 23.99
25.00-10%= 22.50 so, Mr.chang got the better deal ( but not by much.)
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Simplify. (–28xy) ÷ (4) <br><br> –7xy <br> 7xy<br> -1/7xy<br> 1/7xy
Colt1911 [192]
-28xy/4

-7xy

Therefore, the first answer is correct.

Hope this helps!
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Which of the following are true statements?
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3 years ago
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
3 years ago
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