Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:120 units
Step-by-step explanation:
Answer:
-4 and 9
Step-by-step explanation:
-4 + 9 = 5
-4 x 9 = -36
Answer:
x = -3 x=2
Step-by-step explanation:
x^2 + x - 6 = 0
Factor
What two numbers multiply to -6 and add to 1
3*-2 =-6
3+-2 =1
(x+3) (x-2) = 0
Using the zero product property
x+3 = 0 x-2 = 0
x = -3 x=2
