Tell whether the angles are adjacent or vertical. Then find the value of x.

Mathematics

1 answer:

olga55 [171]3 years ago

6 0

Answer:

x=44, They are adjacent

Step-by-step explanation:

since this is right angle it is 90 degrees. You set the whole thing equal to 90, so 43+x+3=90, add 43 and 3=46. Then you subtract 90-46, you get x=44.

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What is the solution to the system of equations?

Over [174]

ANSWER

C) (6,-8)

EXPLANATION

The equations are:

$y = \frac{1}{3}x - 10$

and

$2x+y=4$

We substitute the first equation into the second equation to get:

$2x + \frac{1}{3}x - 10 = 4$

We multiply through by 3 to get:

$6x + x - 30= 12$

Group similar terms,

$6x + x = 30 + 12$

$7x = 42$

Divide both sides by 7 to get,

$x = \frac{42}{7} = 6$

Put this value of x into the first equation to get;

$y = \frac{1}{3} (6) - 10$

$y = 2 - 10 = - 8$

3 0

3 years ago

A cliff forms an angle of x∘ with a lake. If you stand on the edge of the cliff and throw a rock at a distance of 48 ft to the w

klemol [59]

Answer:

∅=6°

Step-by-step explanation:

we have that the distance from the edge of the cliff to the lake is 48 feet, and when the stone is thrown into the lake it collides with the water 5 feet from the base of the cliff so you must find the distance that the stone travels from the edge of the sewer up to 5 feet beyond its base (hypotenuse) and then the angle that forms it (slope)

Hypotenuse (c)

$c^{2}=a^{2}+b^{2}\\c^{2}=48ft^{2}+5ft^{2}\\c^{2}=2304ft^{2} +25ft^{2}=2329ft^{2}\\c=\sqrt{2329ft^{2}}=48.25ft$ :