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balandron [24]
2 years ago
7

The difference between 12 and ten times a number is -28

Mathematics
1 answer:
aev [14]2 years ago
8 0

Answer:

<h2>4</h2>

Step-by-step explanation:

n-\text{the number}\\\\12-10n=-28\qquad|\text{subtract 12 from both sides}\\\\12-12-10n=-28-12\\\\-10n=-40\qquad|\text{divide both sides by (-10)}\\\\\dfrac{-10n}{-10}=\dfrac{-40}{-10}\\\\\boxed{n=4}

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What is 7/10 divided by 2
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Answer:

7/20

Step-by-step explanation:

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3 0
3 years ago
Ok so what really is 9 10?
alina1380 [7]
I am guessing you meant 9+10 which is 19
3 0
2 years ago
Read 2 more answers
PLS HELP ASAP What pattern do you notice about the exponents when dividing two powers with the same base?
Tanya [424]

Answer:

subtract the exponents

Step-by-step explanation:

To divide powers of the same base, you can subtract the exponents.

4 0
2 years ago
What is the equation of the quadratic graph with a focus of (-4,17/8) and a directrix of y=15/8
Temka [501]
So hmm notice the graph below

based on where the focus point is at, and the directrix, then, the parabola is opening upwards, meaning the squared variable is the "x"

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now, keep in mind, the vertex is at coordinates h,k
the vertex itself is half-way between the focus and directrix
the directrix is at y=15/8 and the focus is at y=17/8
so, half-way will then be \bf \cfrac{17}{8}-\cfrac{15}{8}=\cfrac{2}{8}\iff \cfrac{1}{4}

well, so is 1/4 between the focus point and the directrix, half of that is 1/8
so, if you move from the focus point 1/8 down, you'll get the y-coordinate for the vertex, or 1/8 up from the directrix, since the vertex is equidistant to either

what's the "p" distance? well, we just found it, is just 1/8

so, the x-coordinate is obviously -4, get the y-coordinate by 17/8 - 1/8   or 15/8 + 1/8

and plug your values (x-h)² = 4p(y-k)   and then solve for "y", that's the equation of the quadratic

4 0
3 years ago
If y = 9 inches, z = 14 inches, h = 5 inches, and w = 4 inches, what is the area of the object?
vekshin1

Answer:

126

Step-by-step explanation:

7 0
1 year ago
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