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Gemiola [76]
3 years ago
5

Write the equation in slope-intercept form of the line that passes through

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

m = (6-4)/(-1-5) or - 1/3

Step-by-step explanation:

m = (6-4)/(-1-5)

or

- 1/3

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Answer:

CORRECT AMONDO

Step-by-step explanation:

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What is 1 +1 pls HELP
ElenaW [278]

Answer:

2

Step-by-step explanation:

Subject: Re: Need the math proof for 1 + 1 = 2

The proof starts from the Peano Postulates, which define the natural

numbers N. N is the smallest set satisfying these postulates:

P1. 1 is in N.

P2. If x is in N, then its "successor" x' is in N.

P3. There is no x such that x' = 1.

P4. If x isn't 1, then there is a y in N such that y' = x.

P5. If S is a subset of N, 1 is in S, and the implication

(x in S => x' in S) holds, then S = N.

Then you have to define addition recursively:

Def: Let a and b be in N. If b = 1, then define a + b = a'

(using P1 and P2). If b isn't 1, then let c' = b, with c in N

(using P4), and define a + b = (a + c)'.

Then you have to define 2:

Def: 2 = 1'

2 is in N by P1, P2, and the definition of 2.

Theorem: 1 + 1 = 2

Proof: Use the first part of the definition of + with a = b = 1.

Then 1 + 1 = 1' = 2 Q.E.D.

Note: There is an alternate formulation of the Peano Postulates which

replaces 1 with 0 in P1, P3, P4, and P5. Then you have to change the

definition of addition to this:

Def: Let a and b be in N. If b = 0, then define a + b = a.

If b isn't 0, then let c' = b, with c in N, and define

a + b = (a + c)'.

You also have to define 1 = 0', and 2 = 1'. Then the proof of the

Theorem above is a little different:

Proof: Use the second part of the definition of + first:

1 + 1 = (1 + 0)'

Now use the first part of the definition of + on the sum in

parentheses: 1 + 1 = (1)' = 1' = 2 Q.E.D.

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3 years ago
What time is it from where y’all live ?
slava [35]

Answer:

1 Pm

Step-by-step explanation:

6 0
3 years ago
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If possible, please answer in detail :) I need to know if my answers are correct.
g100num [7]

Answer:

Sid : [tied up] This is either really good or really bad.

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A) Find a polynomial, which, when added to the polynomial 5x2–3x–9, is equivalent to: 18
VMariaS [17]

Answer:

a) -5x^{2}+3x+27

b) -5x^{2}+3x+9

Step-by-step explanation:

a) Let the required polynomial be p(x).

We have the relation, 5x^{2}-3x-9 + p(x) = 18

i.e. p(x) = 18 -5x^{2}+3x+9

i.e. p(x) = -5x^{2}+3x+27


b) Let the required polynomial be q(x).

We have the relation, 5x^{2}-3x-9 + q(x) = 0

i.e. q(x) = 0 -5x^{2}+3x+9

i.e. q(x) = -5x^{2}+3x+9

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3 years ago
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