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77julia77 [94]
3 years ago
14

HELP PLEASE I NEED THIS DONE

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

138.3ft^3

Step-by-step explanation:

Volume for cylinders : V = pi*r^2*h

Volume for cones : V = pi*r^2*(h/3)

Since we know the radius (r) is 2 and the height is 10 and 3 for the cylinder and cone respectively, all we do is plug in.

Volume for cylinder is about 125.7ft^3

Volume for cone is about 12.6ft^3

Then just add them together for a total of 138.3ft^3

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Verdich [7]
13.33 is the answer because you multiply them and them add what u got
5 0
3 years ago
What does W prime V prime and U prime equal
choli [55]

Answer:

W' = (0, 1.5)

V' = (1, 2)

U' = (1.5, 0)

Step-by-step explanation:

Multiply each coordinate of the given points by the scale factor 0.5

0*0.5 = 0

3*0.5 = 1.5

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4*0.5 = 2

So thats why W(0,3) becomes W'(0, 1.5), and why V(2,4) becomes V'(1,2), and why U(3,0) becomes U'(1.5, 0)

5 0
4 years ago
12 = 2 + d; d = i am so confused pls help
BaLLatris [955]
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7 0
4 years ago
80 KM is 9% of what distance
ikadub [295]

Answer:

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that determines your answer

you try !

Step-by-step explanation:

5 0
2 years ago
Can someone help me out with some pesky math quiz :) I put a pic
Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to  27

3. The expression (2j4k)^4/5 can be written as \sqrt[4]{32j^{20}k^{5}  }^{5} making the first option the correct option

4. simplifying \sqrt[4]{16x^{4} y^{12} } will result to 2x∛y

5. simplifying \sqrt[5]{2940x^{13} y^{7} } will result to 14x^{6} y^{3} \sqrt{15xy} making the last option the correct option

<h3>How to simplify \sqrt[5]{2940x^{13} y^{7} }</h3>

<u>given data</u>

\sqrt[5]{2940x^{13} y^{7} }

= ( 2940 * x^13 * y^7 )^1/5

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}

multiplying the values inside the parenthesis by ^1/2

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2}  * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15xy)^{1/2}

= ( 14x^6y^3 ) \sqrt{( 15xy)}

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

#SPJ1

3 0
1 year ago
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