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3 years ago

Help it’s for my babies brother hw

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

7 0

Answer:

-3/2, -4/5, -3/10, 1/2, 7/8, 4/3

Step-by-step explanation:

IS THW ANSWER

kodGreya [7K]3 years ago

4 0

Answer:

From left to right, -3/2, -4/5, -3/10, 1/2, 7/8, 4/3

Step-by-step explanation

So what we're trying to do here is to order the numbers from greatest to least.

Let's start off with the negative numbers.

-3/10, -4/5, -3/2.

Now what we want to do is give them all a common denominator to figure out which one is the least of that group.

-3/10,-8/10,-15/10.

Now on to the positive numbers.

1/2, 4/3, 7/8

Turn the denominator into 24.

12/24, 32/24, 21/24

Then put them all in order.

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Citizens are not given the correct information.

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3 years ago

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4 years ago

You had $50. You spent 10% of the money on clothes, 20% on games, and the rest on books. How much was spent inborn books?

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70% on books which is $35. So the answer is 35 .

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4 years ago

Whats the answer? i've been stuck on it for a while:

Archy [21]

Answer:

5:1 (answer c)

Step-by-step explanation:

Number right: 10

Number wrong: 2

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7 0

3 years ago

In Major League Baseball, the American League (AL) allows a designated hitter (DH) to bat in place of the pitcher, but in the Na

hammer [34]

Answer:

Step-by-step explanation:

From the given information:

Let:

$\mu_1$ represent the population mean no. for DH group.

$\mu_2$ represent the population mean no. for no DH group

$n_1$ represent the sample sizes of DH

$n_2$ represent the sample sizes of no DH

Sample size: $n_1 = n_2 = 20$

For both groups, the population standard deviation of runs scored = 2.54

i.e

$\sigma^2_1 = \sigma_2^2 = 2.54$

The null & alternative hypothesis;

$H_o : \mu_1 \le \mu_2 \\ \\ H_a: \mu_1 > \mu_2$

Level of significance:

The test statistics is:

$z = \dfrac{\bar x_1 - \bar x_2}{\sqrt{\dfrac{\sigma^2_1}{n_1} + \dfrac{\sigma_2^2}{n_2} }}$

where;

$\bar x_1$ = sample mean for DH group

$\implies \dfrac{1}{n_1} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(0+6+8+2+2+4+7+7+6+5+1+1+5+4+4+5+7+11+10+0) \\ \\ = \dfrac{92}{20}$

= 4.6

$\bar x_2$ = sample mean for no DH group

$\implies \dfrac{1}{n_2} \sum \limit ^{n_1}_{i=1} x_1 \\ \\ = \dfrac{1}{20}(3+6+2+4+0+5+7+6+1+8+12+4+6+3+4+0+5+2+1+4) \\ \\ = \dfrac{83}{20}$

= 4.15

Now:

$z = \dfrac{4.60- 4.15}{\sqrt{\dfrac{2.54^2}{20} + \dfrac{2.54^2}{20} }} \\ \\ = \dfrac{0.45}{\sqrt{0.32258 +0.32258 }} \\ \\ = \dfrac{0.45}{0.803219} \\ \\$

= 0.5602

Since the test is one-tailed by looking at that $H_a:$

The P-value = $P(Z > z)$

$\implies 1 - P(Z \le z) \\ \\ = 1 - P(Z \le 0.5602)$

Using Excel Function " =normdist(z)"; we have":

$= 1- 0.7123$

P-value = 0.2877

Decision rule: To reject $H_o$ , if $p-value < \alpha \ at \ 0.10$

Conclusion: SInce P = 0.2877 which is $> \ \alpha \ at \ 0.10.$

We fail to reject the $H_o$ and conclude that there is insufficient evidence to support the given claim that: $\text{more runs are scored in games for which DH is used.}$

8 0

3 years ago