Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
D)
Step-by-step explanation:
Answer is D)
Range lies in between -2 and 3
=> -2 <= y <= 3
(-2 less than or equal to y, less than or equal to 3)
Is there an equation with the question? This doesn't mean anything^
The answer is:
The measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.
