All categories

3 years ago

I need the answer for the Linear equation of the below graph

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

Answer:

y = - $\frac{3}{4}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = $\frac{0-3}{4-0}$ = - $\frac{3}{4}$

The line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = - $\frac{3}{4}$ x + 3 ← equation of line

You might be interested in

Please Answerrr! I need help ASAPP!

MArishka [77]

Step-by-step explanation:

5×6 = 30 and 30×8 = 240 divide that by three you get 80

6 0

3 years ago

The ratio of red cars to blue cars in a parking lot was 5:3 . If there was 40 red cars , how many blue cars were there ?

Bas_tet [7]

The answer is x equals 24
you set up a proportion new over old
so for red cars 40 over 5
since we don’t know the new for blue cars we’ll use x
so x over 3
we then make them equal to each other
40 x
—- = —-
5 3
cross multiply, then we get
120=5x
isolate the x by dividing 5 from both sides to get 24

5 0

3 years ago

Need help on this math problem

erik [133]

Answer:

$-5, 18, \sqrt{13}$

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is $\frac{1+x^2}{x+1}$ , and plugging in -3 gets us $\frac{1+9}{1-3}$ , this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as $|9x-15|$ . Plugging in negative one third into the question gets us $|9(-\frac{1}{3})-15|$

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as $\sqrt{-3-8x}$ . Plugging in negative 2, we have $\sqrt{-3-8(-2)}$ . Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13

7 0

3 years ago

Find the value of X in the simplest radical form

Galina-37 [17]

Answer:. 7

Step-by-step explanation:

4 0

3 years ago

What are the solutions to the quadratic equation -2x^2 + 6x + 3 = 0?

mario62 [17]

For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$

5 0

4 years ago