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ohaa [14]
3 years ago
7

Where do you put the points at

Mathematics
2 answers:
kirill115 [55]3 years ago
6 0
The points are placed correctly
artcher [175]3 years ago
4 0

Answer:

what are we doing

Step-by-step explanation:

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Find the area of triangle? 15ft 20ft​
Vikentia [17]

Answer:

I see your profile everywhere, and the answer is Right scalene Pythagorean triangle.

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3 0
3 years ago
HELPPPPPPP!!!!! PLEASEEEE!!!!
maksim [4K]

Answer:x=1012

Step-by-step explanation:

5 0
3 years ago
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Simplify. (x6 y3)(−8xy2)(−6x3)
meriva
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . .  . . \\ \\  x^7  \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \   multiplied \ by \ 2^1   = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{  (2^4*3x^1^0y^5)}}
7 0
3 years ago
What is the equation of the circle with center (0, 0) that passes through the point (-8, 3)?
77julia77 [94]

 

hello :<span>
<span>an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is :  x² +y² = 73</span></span>

7 0
3 years ago
X= 2 and y = 4, then -X-XY
Fed [463]

Answer:

-10

Step-by-step explanation:

= -X - XY

= -2 - 2×4

= -2 - 8

= -10

therefore, -X - XY = -10

5 0
2 years ago
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