n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
G = 1
h = 2
Step-by-step explanation:
4(2h - 3) - 5h = -6
8h - 12 - 5h = -6
3h - 12 = -6
3h = 6
h = 2
g = 2(2) - 3
g = 4 - 3
g = 1
Answer:
shirts = 15 when pants = 6
15
Step-by-step explanation:
Try two others that are given
shirts / pants = 10 / 4 = 2.5
shirts / pants = 30/12 = 2.5
So shirts/pants = 2.5 = x/6
2.5 = x / 6 Multiply by 6
2.5 * 6 = x
x = 15
Answer:
32.5
Step-by-step explanation:
If CED is 65, then AEB is 65, therefore we can calculate that CEA is 115 because 180 - 65 = 115. Then we do 180 - 115 = 65 which is the sum of angles ACE and CAE so 65 / 2 = 32.5 which is CAE.
Hope this helped!
Answer:
(x+6)(x+6)
(x+6)^2
Always remember this identity
(a+b)^2 = a^2 + b^2 + 2ab
So, Now take x=a , 6 =b
Substitute above values
x^2 + 36 +2(x)(6)
=x^2 +36 +12x
=x(x+12) +36
