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prisoha [69]
2 years ago
15

Draw a diagram that shows how the expression can represent the area of a figure 8(3x-1)

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
6 0

Answer:

Step-by-step explanation:

You can draw a rectangle with one side of the rectangle being 8 units, while the other side being (3x - 1) units.

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Ricardo changed $600 into pounds when the exchange rate was $1 = 0.60 pounds
yulyashka [42]

600 x 0.60 = 360 pounds

360 /0.72 = 500

He got $500

8 0
2 years ago
Look at the photo pick A B C D either one explanation not needed thank you! <3
padilas [110]

Answers

A. <

Explanation

-2.875_____ <u>-</u><u>9</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>8

-2.875_____-1.125

so

-2.875 < -1.1225

cause -2 is greater than -1

8 0
2 years ago
90 out of 120 students in your grade are girls at your school. What percentage are boys?
sesenic [268]
30% Bc there are 30 boys and 90 girls or it’s 10% boys
7 0
3 years ago
Pls help me solve this
NISA [10]

Answer:

$50

Step-by-step explanation:

12 x 30 = 360

960 - 360 = 600

600/12 = 50

3 0
2 years ago
Read 2 more answers
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
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