I think it's D but I'm not %100 sure
Step-by-step explanation:
√3 x² - 2x - √3 = 0
√3 x² - 3x + x - √3 = 0
√3 x(x - √3) + 1(x - √3) = 0
(x - √3 ) (√3 x + 1) = 0
x - √3 = 0 , √3 x +1 = 0
x = √3 , x = -1/√3
Answer:
Step-by-step explanation:
If (x + 2) is a factor of a polynomial then ( - 2 ) is the zero of that polynomial ⇒ ( - 2 )³ + 2( - 2 )² + 2( - 2 ) + k = 0 ⇒ k = - 4
The solution is 2sqrt77/77. You just fill in 2/3 for the x's. When you do that, you do that you get (2/3)/sqrt(9-[2/3]^2) which, simplified, is (2/3)/sqrt(9-[4/9]). Now use the common denominator under the radical of 9 to get (2/3)/sqrt([81-4]\9). Simplifying even further gives you (2/3)/([sqrt(77)]/3). Now do that division by multiplying 2/3 by the reciprocal of ([sqrt(77)]/3) to get 2/sqrt77. I rationalized the denominator to get that result up there.
