Answer:
a) x = 30°
b) mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
Question:
The complete question as found on Chegg website:
In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
intercepted have the following ratio of measurements:
mRS : mST :MTU : mUR=1:4:4:3
(a) If mRS = x, then write an equation that could be used to solve for x
and find the value of x.
(b) State the measure of each of the four arcs.
mRS =
mST =
MTU
MUR =
Step-by-step explanation:
Find attached the diagram related to the question
mRS : mST : mTU : mUR = 1:4:4:3
Since mRS = x
Writing the ratios of the measure of angle in terms of mRS:
mST = 4× mRS = 4×x = 4x
mTU = 4× mRS = 4×x = 4x
mUR= 3× mRS = 3×x = 3x
The sum of measure the 4 measures of arc = 360° (sum of angle in a circle)
mRS + mST + mTU + mUR = 360°
x + 4x + 4x + 3x = 360
12x = 360
x = 360/12
x = 30°
b) The measure of angle
mRS = x = 30°
mST = 4x = 4(30°) = 120°
mTU = 4x = 4(30°) = 120°
mUR = 3x = 3(30°) = 90°
251,782.
Just add 3*16,454 to the original number.
Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours

The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours

The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
![\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20c%5E2%3D18%5E2%2B33%5E2%20%5C%5C%20c%5E2%3D324%2B1089%20%5C%5C%20c%5E2%3D1413%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B1413%7D%20%5C%5C%20c%3D37.59%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
The two ships are 37.59 nautical miles apart after 1.5 hours.