Question

Pythagoras help needed please

Answer 1

Answer:

See explanation

Step-by-step explanation:

Find the diagonal of the square. The side of the square is 5 cm long. By the Pythagorean theorem,

$\text{Diagonal}^2=\text{Side}^2+\text{Side}^2\\ \\\text{Diagonal}^2=5^2+5^2\\ \\\text{Diagonal}^2=25+25\\ \\\text{Diagonal}^2=50\\ \\\text{Diagonal}=\sqrt{50}=5\sqrt{2}\approx 7.07\ cm$

If the square (being inside the circle) touches the circle, then the diagonal of the square is exactly the diameter of the circle. The diameter of the circle is twice the radius of the circle, so

$\text{Diameter}=2\times 5=10\ cm$

Since the diagonal is shorter than the diameter, the square can fit into the circle without touching the circle.