Elimination method 10x-4y=-8 -5x+6y=10
1 answer:
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Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean, = 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;
Plugging in the values, we have;
Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.
Answer:
The sign is negative
Step-by-step explanation:
Given
Required
Determine the sign
The expression can be split into 3 factors
If x > 0 then x is positive and If y < 0 then y is negative
So, the expression becomes:
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Leave only signs
So, we have:
So, we have:
<em>Hence, the sign of the expression is negative</em>
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Take for instance;
The expression would be:
-- negative