-10p+9=12
-9 -9
-10p=3
—— —
-10 -10
P=3/-10 or -0.3
Answer:
1). All four triangles are right-angled.
3.) All four triangles are congruent.
4) Area of a rhombus = 4 x area of one triangle.
Step-by-step explanation:
If a rhombus is cut into four triangles using diagonals, the three statements that would apply to any rhombus would be that 'all those four triangles would be right-angled,' 'the triangles would be congruent to one another,' and 'area of one triangle * 4 would be equal to the area of the rhombus.'
As we know, the diagonals bisect one another in a rhombus at 90° and the angles opposite to one another are equal. This <u>proves that all four triangles constructed through the diagonals would be ≅ through SSS congruency and perpendicular to one another because the corresponding edges of the congruent triangles are also ≅</u> . Since the rhombus is divided into four equal parts, the area of one triangle into four would be equals to the area of the rhombus. Thus, <u>options 1, 3, and 4</u> are the correct answers.
They will cost $54
i know this because if youre getting 40% off, you will have to pay 60% of the total cost
so, 90 x .60 = 54
let me know if you have any further questions
:)
step-by-step explanation:
every time we see "a number" or "the same number," we can add a variable (we'll use x here). rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of x and 9.
next, we can work backwards to write an inequality. we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.
for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9. so now the inequality should look like this: 2x - 8 > x + 9.
now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.
then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15
hope this helps! <em>:)</em>
When you round that number you get 7,000
