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2 years ago

How do you do solve 13 a and b?

Mathematics

2 answers:

tiny-mole [99]2 years ago

7 0

Answer:

Step-by-step explanation:

Let A=ax²+bx+c

x=1,A=a+b+c or 7=a+b+c ...(1)

x=2,A=4a+2b+c or 12=4a+2b+c ...(2)

x=3,A=9a+3b+c or 15=9a+3b+c ...(3)

subtract (1) from (2) & (3)

3a+b=5 ...(4)

8=8a+2b

or 4a+b=4 ...(5)

subtract (4) from (5)

a=-1

from (4)

-3+b=5

b=5+3=8

b=8

from (1)

-1+8+c=7

c=0

so A=-x²+8x

thus table shows it is quadratic.

A=-x²+8x=-(x²-8x+16-16)

or A=-(x-4)²+16

vertex is (4,16)

german2 years ago

6 0

For a you have to find the formula. for ex. 1+x=7 so you solve for x.

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The sum of two integers is 66. The larger is 12 less than five times the smaller. Find the two integers

VikaD [51]

Answer:

13 and 53

Step-by-step explanation:

First Integer: x

Larger integer: 5x-12

66=x+(5x-12)

66= x+5x-12

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78=6x

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First Integer: 13

Larger Integer: 13*5-12= 65-12=53

Check Work:

13+53=66

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Step-by-step explanation:

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