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Alina [70]
2 years ago
12

Pleasee help middle school math​

Mathematics
1 answer:
Tomtit [17]2 years ago
8 0
1 < 15 - 2a < 7. That is the answer
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there are 200 end of the year school dance tickets students who have perfect attendance are able to presage them in advance if 1
Umnica [9.8K]

200 - 18 = 182
182 is the answers
3 0
2 years ago
C)PLEASE MAN PEOPLE ARE USING ME FOR POINTS
UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

<u>Interquartile Range: </u>

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

<u>Range:</u> 8 - 1 = 7

<u>Variance: </u>

We start by determining the mean,

\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571

5.3

<u>Standard Deviation</u>

We take the square root of the variance,

\sqrt{5.28571} = 2.29906

2.3

If you are not familiar with variance and standard deviation, just leave it.

3 0
2 years ago
Read 2 more answers
a triangle has an area of 54 m2 and a height of 9m how long is the base of the triangle entered your answer in the box
Delvig [45]
Answer:
base of the triangle = 12 m

Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m

Substitute in the equation to get the base as follows:
Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m

Hope this helps :)
7 0
2 years ago
Read 2 more answers
(01.06 MC) Jonna is 4 years older than her brother. Which of the following expressions shows the sum of their ages if b represen
Lana71 [14]
Your equation will be: b+4
6 0
3 years ago
4a/3-b/4=6<br> 5a/6+b=13<br> Solve linear system by elimination
kondor19780726 [428]
\bf \cfrac{4a}{3}-\cfrac{b}{4}=6&#10;\qquad \qquad &#10;\cfrac{5a}{6}+b=13&#10;\\\\\\&#10;\textit{let us remove the denominators off those folks}\\&#10;\textit{by multiplying the first one by 12, both sides}\\&#10;\textit{and the second one by 6, both sides, thus}&#10;\\\\\\&#10;12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72&#10;\\\\\\&#10;6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78

\bf  \textit{now, let's do the elimination}&#10;\\\\&#10;&#10;\begin{array}{llll}&#10;16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\&#10;5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\&#10;&&--------\\&#10;&&58a+0\quad=372&#10;\end{array}

solve for "a", once you get "a", plug it back into either equation to get "b"
3 0
2 years ago
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