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Brrunno [24]
3 years ago
14

The area of the triangle below is 8.91 square inches. What is the length of the base?

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0
I think the answer is 19.602 hope this helps!
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Starting at the same point, Tom and Juanita go biking in opposite directions. If Tom rides at a speed of 14 mph, and Juanita rid
ANTONII [103]

See https://web2.0calc.com/questions/please-help_96053.

7 0
3 years ago
When simplified (v2 – y + 1) + (4y2 – 3y - 2) is:
olchik [2.2K]

Answer:

  D.  5y^2 - 4y - 1

Step-by-step explanation:

Combine like terms:

  (y^2 -y +1) +(4y^2 -3y -2)

  = y^2(1 +4) +y(-1-3) +(1 -2)

  = 5y^2 -4y -1

8 0
3 years ago
Solve each system of equations <br> 2x- 5y = 7<br> 3x - y = -9
Darina [25.2K]

Answer:

x = -4; y = -3

Step-by-step explanation:

2x - 5y = 7

3x - y = -9

Rewrite top equation. Multiply both sides of bottom equation by -5. Add equations. This eliminates y, and we solve for x.

         2x - 5y = 7

(+)   -15x + 5y = 45

----------------------------

      -13x         = 52

Divide both sides by -13.

x = -4

Substitute -4 for x in the first original equation and solve for y.

2x - 5y = 7

2(-4) - 5y = 7

-8 - 5y = 7

-5y = 15

y = -3

Answer: x = -4; y = -3

-5 =

8 0
3 years ago
Pls help me with trig :)
trapecia [35]

Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

\frac{GH}{EH}=tan x\\GH=EH~ tan x\\or~ GH=a ~tan x=6 tan x\\\frac{GH}{FH}=tan (90-x)=cot x\\GH=FH*cot x\\GH=b*cot x=27 cot x\\6 tan x=27 cotx\\\frac{tan x}{cot x}=\frac{27}{6}\\tan ^2 x=\frac{27}{6}=\frac{9}{2}\\sec^2x-tan^2x=1\\sec^2 x=1+tan ^2x=1+\frac{9}{2}=\frac{11}{2}\\\frac{EG}{EH}=sec x\\ EG=EH sec x=a sec x= 6 sec x=6\sqrt{\frac{11}{2} } =3\sqrt{22} \approx 14.07

4 0
3 years ago
What is the answer???
Agata [3.3K]
3/4 gone because she was making 1 batch so that 4/4 she spilled 1/4 so whats left is 3/4
4 0
3 years ago
Read 2 more answers
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