Need help with number 20

Mathematics

1 answer:

svetoff [14.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

Since we are given BC is congruent to DC and angle b and d are 90. We can prove that <C is congruent to itself by reflexive property of congruence. We can also you use linear pair theorem to prove <CDA is congruent to <CBE. Since they are right angles, we can prove that they are congruent by rt <s thm. Thus, we cna prove they are congruent by ASA. Hope it helps

You might be interested in

Determine algebraically whether the function is even, odd, or neither even nor odd.

m_a_m_a [10]

For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x) [No Relation]

(-x)^n = x^n for n -> even
(-x)^n = -x^n for n -> odd
In your example:

f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1 ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x) [between the bracket was the original fn]

f(x) = - f(-x)
so the function is odd also called symmetric about the origin

7 0

3 years ago

Marla writes the problem, 628 divided by 1300.

Maslowich

Answer:

628/1300

Step-by-step explanation:

These are what would represent her problem..

8 0

3 years ago

Read 2 more answers

Define the set X = {(x,y)|x > 0,y ≤ √x}.

Kitty [74]

The set X is convex.

In geometry, a subset of an affine space over the real numbers, or more broadly a subset of a Euclidean space, is said to be convex if it contains the entire line segment connecting any two points in the subset. A solid cube is an example of a convex set, whereas anything hollow or with an indent, such as a crescent shape, is not. Alternatively, a convex region is a subset that crosses every line into a single line segment.

b)The set X is convex as any two points on the set X is included in the whole set as x>0. So a line joining any two points on the set X is completely inside the set x.

c)set X is not a closed set as the compliment of the set is not an open set.

d)Set X is not bounded. If a set S contains both upper and lower bounds, it is said to be bounded. A set of real numbers is therefore said to be bounded if it fits inside a defined range. hence set x is not bounded.

To learn more about convex sets:

brainly.com/question/12577430

#SPJ9