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Nonamiya [84]
4 years ago
5

HELP FAST PLEASE PICTURE ATTACHED

Mathematics
1 answer:
Vinvika [58]4 years ago
8 0
N = 15

24÷2=12+3=15

........

check

15 -3 = 12

12 × 2 = 24
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25 − (8 − 4) ÷ 6 • 3=what plzzzz answer!<br> Will mark Brainliest!!!!
serg [7]
25 - (8-4) /6 *3 = 25 - 2 / 6 * 3
=25-1
=24 #


“/”= divide
“*”= multiply
4 0
3 years ago
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All of these have to be estimated using the chart shown^
umka21 [38]
Dont click that link its a virus
4 0
3 years ago
I don’t know the answer please help !
Shalnov [3]

Answer:

1. 24

2. 24

3. -24

4. -24

I don`t know why some of the answers are 10, I think those are just trick ones. The answers are only in 24s

7 0
3 years ago
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How many times larger than 2x10^3 is 6x10^6?
Zielflug [23.3K]

Answer: 5,998,000

Step-by-step explanation:

2x10^3= 2,000

6x10^6= 6,000,000

In translation, Use 1 x The Initial SIG FIGS, or first numbers. 10x10 is 100, and notice how 10 and 10 have 2 zeros, so 1x1 = 1 +00 is a way to construct the number.

In this case, the 10^x, the x can represent the number of zeros after our first value.

So, 6 + six zeros, or 6,000,000

and, 2 + 3 zeros, or 2,000

To find the difference, subtract the numbers from eachother and extract the absolute value, (meaning the final answer won't be negative).

So, 6,000,000 - 2,000 = 5,998,000, which is the answer to the prompt!

Hope this Helped!

3 0
3 years ago
A portion of the Quadratic Formula proof is shown. Fill in the missing reason.
hram777 [196]

Answer:

see the procedure

Step-by-step explanation:

we have

ax^2+bx+c=0 ----> given

step 1

Subtract c from both sides of the equation

ax^2+bx+c-c=-c

ax^2+bx=-c

step 2

Factor the leading coefficient a

a(x^2+\frac{b}{a}x)=-c

step 3

Complete the square and add to both sides

a(x^2+\frac{b}{a}x+(\frac{b^2}{4a^2}))=-c+\frac{b^2}{4a}

step 4

Divide both sides of the equation by a

(x^2+\frac{b}{a}x+(\frac{b^2}{4a^2}))=-\frac{c}{a}+\frac{b^2}{4a^2}

step 5

Find a common denominator on the right side of the equation  and adds the fractions together on the right side of the equation

(x^2+\frac{b}{a}x+(\frac{b^2}{4a^2}))=\frac{b^2-4ac}{4a^2}

step 6

Rewrite the perfect square trinomial as a binomial squared on the left side of the equation

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

step 7

Take the square root of both sides of the equation

(x+\frac{b}{2a})=\pm\frac{\sqrt{b^2-4ac}}{2a}

step 8

Subtract both sides of the equation by the term b/2a

x=-\frac{b}{2a}\pm\frac{\sqrt{b^2-4ac}}{2a}

step 9

Rewrite the final expression

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

8 0
3 years ago
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