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3 years ago

Create a quadratic polynomial function f(x) and a linear binomial in the form (x − a).

1 answer:

7 0

Quadratic polynomial x^2 - x - 6 = f(x)
binomial (x-3)

dividing:-
x + 2
----------------------
x - 3 ) x^2 - x - 6
x^2 - 3x
----------
2x - 6
2x - 6
--------
.........

result of division is (x + 2)
s o we can write the function as (x - 3)(x + 2)

Part 2 f(a) = f(3) = (3)^2 - 3 - 6 = 0

Part3 The remainder Theorem states that the remainder when a polynomial is divided by (x - a) then the remainder is f(a). If f(a) = 0 then x - a is a factor.
In the above case f(3) = 0 therefore (x - 3) is a factor of our polynomial.

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Convert the following unsigned binary number to unsigned decimal.<br><br> 110011.101

tangare [24]

Answer:

51.625

Step-by-step explanation:

Given a unsigned binary number, to calculate the unsigned decimal:

first, starting at dot, you list the positive powers of 2 from right to left beginning in $2^{0}$ that is equal to “1”. Increase by one the exponent in every power until you complete the total quantity of digits from the unsigned binary number. In this case, since dot to the left, the binary number has six digits (110011). That is to say that you get the followings powers: $2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ .

Second, do the same from dot to the right but this time, you list the negative powers of 2 from left to right beginning in $2^{-1}$ that is equal $\frac{1}{2}$ = 0.5. so you get: $2^{-1}$ $2^{-2}$ $2^{-3}$

Now, join two parts and you get:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

Then, you write the equivalent of each of the power below from corresponding binary digit, like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

Finally, you write under the line the equivalent of each power that corresponding to “1” and write “0” under the line, the one that corresponding to “0”, and you sum each one of finals values. Like that:

$2^{5}$ $2^{4}$ $2^{3}$ $2^{2}$ $2^{1}$ $2^{0}$ $2^{-1}$ $2^{-2}$ $2^{-3}$

1 1 0 0 1 1. 1 0 1

| | | | | | | | |

32 16 8 4 2 1 0.5 0.25 0.125

_______________________________________

32 16 0 0 2 1 0.5 0 0.125

32 + 16 + 0 + 0 + 2 + 1 + 0.5+ 0 + 0.125 = 51.625

So that the equivalent from unsigned binary number 110011.101 to unsigned decimal is 51.625

5 0

3 years ago

*ANSWER PLS TYY* Which of the following statements is TRUE about finding the area of a polygon? a.) You can use a coordinate pla

ruslelena [56]

Answer:

The answer to this question is b)

3 0

3 years ago

Read 2 more answers

You've purchased a lottery ticket and your numbers are 5-3-1. A lottery official randomly selects three balls from a set of eigh

Inessa05 [86]

Answer:

1 out of 336 chance

Step-by-step explanation:

Since you picked three numbers, you are going to put three blanks.

What to do in this situation is to have _ _ _. Since there are numbers 1-8, what you want to do is take the three biggest numbers and multiply them together. in this case, they would be 8-7-6. Multiply that and you get 336.

8 0

2 years ago

A six-week fitness program was designed to decrease the time it takes retired individuals to walk one mile. At the beginning of

valkas [14]

Answer:

c. The sampling distribution of the sample means can be assumed to be approximately normal because the distribution of the sample data is not skewed

Step-by-step explanation:

From the given data, we have;

The category of the sample = Retired individuals

The number of participants in the sample = 20

The duration of program = six-weeks

The improvement seen by most participants = Little to no improvement

The improvement seen by few participants = Drastic improvement

Therefore, given that the participants are randomly selected and the majority of the participants make the same observation of improvement in the time to walk a mile, we have that, the majority of the outcomes show little difference in walk times after the program, therefore, the distribution of the sample data is not skewed and can be assumed to be approximately normal

7 0

3 years ago

I need the answers for 6,7,8,9,10,11 pls fast

Natalka [10]

Answer:

6) common denominator = 54

7) common denominator = 80

8) common denominator = 108

9) least common denominator = 10

10) least common denominator = 24

11) common denominator = 21

Step-by-step explanation:

6) common denominator of 1/6 , 1/9

example: A/B where A is de numerator and B is the denominator.

common denominators are numbers that have te same composition

1/6 , 1/9 ⇒ if we want to add this fractions we need to find the common denominator.

therefore: (1/6)*(9/9) , (1/9)*(6/6) ⇒ ((1*9)/(6*9)) . ((1*6)/(9*6)) ⇒ 9/54 , 6/54

the common denominator is 54

7) 3/8 , 3/10

(3*10)/(8*10) , (3*8)/(10*8) ⇒ 30/80 , 24/80

common denominator of this two fractions is 80

Note: We can see that the common denominator can be find just by multiplying the denominators. in 7) 6*9=54 and in 8) 10*8=80. This is because in this cases we are asked just for the common denominator

9) 1/9 , 5/12 ⇒ common denominator = 9*12 = 108

10) Least common denominator of 2/5 , 1/10

in this case is the smmallest number that the denominator have in common:

first, from 2/5: denominator=5

multiples of 5: ⇒5, 10, 15, .........

then from 1/10: denominator=10

multiples of 10 ⇒ 10, 20, 30,....

The least common denominator is the smalles number this two denominators have in common. We can see that this number is 10.

There are other ways because you should also think of it as the minimun common denominator. 5 =5*1 and 10 = 2*5 (minimun expresions)

the least minimun denominator willbe the one that includes all de numbers included in their minimum expresion without making it doble (just the amount of times to make the denominator number in each fraction).

therefore we would know that the least common denominator in this fractions is: 1*2*5 = 2*5 = 10

But just have fun and make it simple

10. least common denominator for: 5/6 , 3/8

first: 5/6 ⇒ denominator: 6, so ⇒ 6, 12, 18, 24, 30, 36.....

then: 3/8 ⇒ denominator: 8, so ⇒ 8, 16, 24. 32, 40....

least common denominator for this fractions is ⇒24

or also:

5/6 ⇒ denominator is 6 ⇒ 6=2*3

3/8 ⇒ denominator is 8 ⇒ 8=2*2*2

least common denominator for this fractions is ⇒ 2*2*2*3 =24

11. common denominator of: 1/3 , 2/7

because in this case 3 and 7 are in their minimum expresion ⇔ 3=1*3 & 7=1*7

we can jus find the common denominator by multiplying both denominators:

7*3=21

Hope it helps.

8 0

3 years ago