6 and 7 are more than 5 units away
A = 5a
B = 2x
C = 6x^2
D = 5/7
E = 2/11
F= 6/x^2
G = 6a
H = -7x
Answer:
41.57
Step-by-step explanation:
took the test
Answer:
See explanation
Step-by-step explanation:
Consider triangles PTS and QTR. In these triangles,
- given;
- given;
- as vertical angles when lines PR and SQ intersect.
Thus,
by AAS postulate.
Congruent triangles have congruent corresponding sides, so

Consider segments PR and QS:
![PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]](https://tex.z-dn.net/?f=PR%3DPT%2BTR%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CQS%3DQT%2BTS%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CPT%3DQT%5C%20%5B%5Ctext%7BProven%7D%5D%5C%5C%20%5C%5CST%3DRT%5C%20%5B%5Ctext%7BGiven%7D%5D)
So,
![PR=SQ\ [\text{Substitution property}]](https://tex.z-dn.net/?f=PR%3DSQ%5C%20%5B%5Ctext%7BSubstitution%20property%7D%5D)
Hello!
<span>9 - 2 x 3 x 3 + 18
9 - 18 + 18
=9
9 is your answer.
Enjoy.
Brainliest please?
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