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soldi70 [24.7K]
2 years ago
5

Please help me with this homework!

Mathematics
1 answer:
ZanzabumX [31]2 years ago
5 0
<h2><u>Part 1: Define</u></h2><h3>Part 1i) Defining "adjacent angles"</h3>

In this case, adjacent angles are such pairs of angles that are alongside each other. Therefore, we can say that the sum of the two adjacent angles forms a bigger angle.

<h3>Part 1ii) Defining "vertical angles"</h3>

In this case, vertical angles are such angles that are on opposite sides of the intersection between two lines. It is understood that vertically opposite angles are equivalent.

<h2><u>Part 2: Solve</u></h2><h3>Problem 8:</h3>

Clearly, we can see that two angles (one angle known as ∠x and the other angle) are alongside each other. Therefore, we can tell the angles are adjacent angles.

As we can see a \square, we can tell that the sum of the measure of ∠x and the other angle is 90°. Therefore, we obtained;

  • ⇒ ∠x + 35 = 90
  • ⇒ ∠x = 90 - 35
  • ⇒ ∠x = 65°

Therefore, the measure of ∠x is 65°.

<h3 /><h3>Problem 9:</h3>

Clearly, we can see that two angles (one angle known as ∠x and the other angle) are on opposite sides. Therefore, we can tell that the angles are vertically opposite angles.

As stated in part 1ii, vertical angles are equivalent. Since ∠x and the other angles are vertically opposite angles, the measure of ∠x is 128°.

<h3 /><h3>Problem 10:</h3>

Clearly, we can see that two angles (one angle known as ∠x and the other angle) are alongside each other. Therefore, we can tell the angles are adjacent angles.

Since the line shown, is a straight line, we can tell that the sum of 117 and x is 180. Therefore, we obtain the following equation;

  • 117 + ∠x = 180°

<u>When isolating x, we get;</u>

  • ⇒ 117 + ∠x - 117 = 180° - 117
  • ⇒ ∠x = 180° - 117
  • ⇒ ∠x = 63°

Therefore, the measure of ∠x is 63°

Learn more about this topic: brainly.com/question/14355129

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For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
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Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

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