I think is D cuz all Yoou really need to do is look at the graph
Answer:
The ratio of the escape velocity to the orbital velocity is
.
Explanation:
The minimum velocity given to an object so that it escapes from the earth's gravitational pull is called escape velocity.
The formula of the escape velocity is

The velocity of an object in the orbit around the earth is called orbital velocity.
The formula of the orbital velocity is

The ratio of the escape velocity to the orbital velocity is
Answer:
The momentum of the bowling ball is 53.4 kg-m/s.
Explanation:
We have,
Mass of a bowling ball is 8.9 kg
Speed of the ball is 6 m/s
It is required to find the momentum of the ball. The momentum of an object is given in terms of its mass and speed as :
p = mv

So, the momentum of the bowling ball is 53.4 kg-m/s.
Answer:
27,000 m
450 m/s
Explanation:
Assuming the initial velocity is 0 m/s:
v₀ = 0 m/s
a = 15 m/s²
t = 60 s
A) Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²
Δy = 27,000 m
B) Find: v_avg
v_avg = Δy / t
v_avg = 27,000 m / 60 s
v_avg = 450 m/s