What is 34 + (5) × (1.2465) written with the correct number of significant figures?
1 answer:
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>
mass = 4 kg
velocity = 5 m/s^2
<h3 /><h3>Orange truck:</h3>Mass= 2kg
Velocity = 7m/s^2
<h3 /><h3>Grey Car:</h3>mass = 6 kg
velocity = 4m/s^2
<h3 /><h3>Green Car:</h3>Mass = 8 kg
Velocity = 3 m/s^2
<h2>_____________________________________</h2><h2>SOLUTION:</h2>By the equation of kinetic energy,
K.E =
Where,
K.E is kinetic energy
m is mass
v is velocity
<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>
Directly substitute the variables in the equation,
K.E =
Simplify the equation,
K.E = 50 J
<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>
Directly substitude the variable in the equation,
K.E =
Simplify the equation,
K.E = 48J
<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />Substitute the variables in the equation,
K.E =
Simplify the Equation,
K.E = 36J
<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />Substitute the variable,
K.E =
Simplify the equation,
K.E = 49J
<h2>_____________________________________</h2>As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />
By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m
K.E = 1/2 x 0.17 x
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/
To calculate the final velocity, let us use third equation of motion.
=
+ 2as
=
+ 2 x 0.3 x 61
= 36 + 36
= 72
V =
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
Learn more about dynamics here: brainly.com/question/402617