Answer:
The left train travels 2378 m until it reaches the meeting point.
Explanation:
The equation for the position of the trains is the following:
x = x0 + v · t
Where:
x = position at time t
x0 = initial position
v = velocity
t = time
If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.
At the meeting point, the position of both trains is the same:
x left train = x right train
x0₁ + v₁ ·t = x0₂ + v₂ · t
0m + 29 m/s · t = 4744.6 m - 29 m/s · t
58 m/s · t = 4744.6 m
t = 4744.6 m / 58 /s
t = 82 s
The position of the left train at that time will be:
x = x0 + v · t
x = 0 m + 29 m/s · 82 s
x = 2378 m
The left train travels 2378 m until it reaches the meeting point.
Answer:
a. Picture attached
b. V, X
c. 
d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).
Explanation:
First we have to identify the unknown of this problem:

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

If we reorganize the equations, considering that
and
are zero because motion starts from rest , we have:

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.
Hi there!
So, I believe an <em>isobar</em> connects areas of the same atmospheric pressure, and an <em>isotherm</em> connects areas of the same temperature. Hope this helped :)
Answer:
The potential energy is transformed into kinetic energy
Explanation:
This particular case is defined as the principle of energy conservation since energy is not created or destroyed only transforms. When you have potential energy it can be transformed into kinetic energy or vice versa. In this problem, we have the case of a ball that sits on a desk and then falls to the ground. In this way the ground will be taken as a reference point, this is a point at which the potential energy will be equal to zero in such a way that when the ball is on the desktop that is above the reference line its potential energy will be maximum. As the ball drops its potential energy decreases, as the height relative to the ground (reference point) decreases. In contrast its kinetic energy increases and increases as it approaches the ground. So when it hits the ground it will have maximum kinetic energy and will be equal to the potential energy for when the ball was on the desk.
Therefore:
![E_{p} = potential energy [J] = E_{k} = kinetic energy [J]where:\\E_{p} =m*g*h\\m =mass [kg]\\g=gravity[m/s^2]\\h=elevation[m]\\E_{k} = \frac{1}{2} *m*v^{2} \\where:\\v=velocity [m/s]\\\frac{1}{2} *m*v^{2} = m*g*h](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3D%20potential%20energy%20%5BJ%5D%20%3D%20E_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5Dwhere%3A%5C%5CE_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cm%20%3Dmass%20%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D%5C%5CE_%7Bk%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%20%5C%5Cwhere%3A%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%20%2Am%2Av%5E%7B2%7D%20%3D%20m%2Ag%2Ah)
Which type of mirror always has an image that is smaller than the object?
convex