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3 years ago

HELP ME ANSWER THIS PLEASEE!

Mathematics

2 answers:

Olegator [25]3 years ago

5 0

Answer:

no solution

Step-by-step explanation:

lana [24]3 years ago

5 0

Answer:

wala po akong alamwrbdjdbee

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ABCD is a quadrilateral inscribed in a circle, as shown below:

malfutka [58]

Answer:

Option 4: (2x + 16)° + (x)° = 180°

Step-by-step explanation:

See the attached figure.

For a quadrilateral inscribed in a circle

The opposite angles are supplementary.

So, ∠D + ∠B = 180°

From the figure:

∠B = x° and ∠D = (2x+16)°

∴ (2x + 16)° + (x)° = 180°

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

S_A_V [24]

Answer:

$\frac{16x^2+48x}{8x} = 2x+6\\\frac{56x^2-14x}{7x} = 8x-2\\\frac{18x^2+15x}{3x}=6x+5\\\frac{20x^2-32x}{4x}=5x-8$

Step-by-step explanation:

We will solve the division one by one:

$\frac{16x^2+48x}{8x} = \frac{8x(2x+6)}{8x} = 2x+6\\\frac{56x^2-14x}{7x}=\frac{7x(8x+2)}{7x}=8x+2\\\frac{18x^2+15x}{3x} =\frac{3x(6x+5)}{3x} = 6x+5\\\frac{20x^2-32x}{4x}=\frac{4x(5x-8)}{4x}=5x-8$

6 0

3 years ago

Read 2 more answers

Please answer. I have attached the picture of the question and I promise I will give brainliest.

Vaselesa [24]

Answer:

first is the chart so for the time row its 4, 8, 12, 16, 20 & distance is 3, 6, 9, 12, 15

I added the complete graph down below, basically what i did wasplot the points from the chart so (4,3), (8,6), (12,9), (16, 12), and (20,15)

so for example for (4,3) you would first find 4 on the x-axis or the time line and then find 3 on the y-axis and so on let me know if you can see the picture:)

8 0

3 years ago

(-5, 3), (2, 1) what is the slope of the line that passes through the points

lord [1]

Here is a photo of how to solve it

3 0

4 years ago

PLEASE HELP

Georgia [21]

9514 1404 393

Answer:

10
12%: 4.8 L; 32%: 3.2 L

Step-by-step explanation:

For mixture problems, I like to use a single variable to represent the quantity of the greatest contributor (greatest cost or greatest concentration). Let that variable be x.

1. In this problem, the amount of the greatest contributor is already fixed, so we'll use x for the amount of walnuts. The cost of the mix is ...

0.80x + 1.25(8) = 1.00(x +8)

2 = 0.2x . . . . . . . . . . . . . . . . . subtract 0.8x+8, simplify

10 = x . . . . . . . . . divide by 0.2

10 pounds of walnuts must be used.

2. The amount of acid in the mix is ...

12%(8 -x) +32%(x) = 20%(8)

20%(x) = 8%(8) . . . . . . . . . . . . subtract 12%(8)

x = 8(8)/20 = 3.2 . . . . . . . . . . divide by 20%

8-x = 4.8

3.2 liters of 32% acid must be mixed with 4.8 liters of 12% acid

_____

Comment on mixture problems

The general solution for mixture problems that have a greater contributor (G), a lesser contributor (L), and a mix value (M) is ...

g/l = (M -L)/(G -M) . . . . . . ratio of quantities of G and L

In the first problem, this becomes ...

8/l = (1.00 -.80)/(1.25 -1.00) = .2/.25 = 4/5 ⇒ l = 8(5/4) = 10

In the second problem, this becomes ...

g/l = (20-12)/(32-20) = 8/12 = 2/3 ⇒ g = (2/5)(8) = 3.2; l = (3/5)(8) = 4.8

In this case, we recognize that the ratio of 2 parts to 3 parts means that the greater contributor is 2 of 5 total parts.

4 0

3 years ago

Read 2 more answers