✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as

Thus, 13.89% of students are willing to report cheating by other students.
31.62
You use pythagorean theorem so 30 is legA and 10 is legB so 20^2+10^2= square root legC which is 31.62