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3 years ago

Help with question 2 very confused

Mathematics

1 answer:

givi [52]3 years ago

8 0

Answer:

im confused too lol

Step-by-step explanation:

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in the previous question, what is the distance from a side of the triangle to the incenter? can someone also explain how to get

denis23 [38]

In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle. An incircle is roughly sketched in the accompanying diagram.

Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.

Answers:
The value of x = 2
The distance from incentre to side of triangle is 7

5 0

2 years ago

For a particular event, 771 tickets were sold for a total of $3037. If students paid $3 per ticket and non-students paid $5

BlackZzzverrR [31]

Answer:

Number of student tickets were sold = 409

Step-by-step explanation:

Total number of tickets sold = 771

I.e Students ticket (S) + Non students ticket(N S) = 771

Total amount to be paid for tickets = $ 3037

Amount paid by students per tickets = $3

Amount paid by non-students per tickets = $5

So, according to question

S + NS = 771

3 S + 5 NS = 3037

Solve both equations

5 S + 5 NS = 771 × 5

3 S + 5 NS = 3037

so ,

(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037

Or, 2 S = 818

I.e S = $\frac{818}{2}$ = 409

Hence, The number of student tickets were sold = 409 Answer

5 0

2 years ago

What is the completely factored form of d4 − 81?

lilavasa [31]

For this case we must factor the following expression:

$d ^ 4-81$

Rewriting the expression:

$(d ^ 2) ^ 2-9 ^ 2$

We factor using the formula of the square difference:

$a ^ 2-b ^ 2 = (a + b) (a-b)$

Where:

$a = d ^ 2\\b = 9$

So:

$(d ^ 2 + 9) (d ^ 2-9)$

From the second term we have:

$d ^ 2-3 ^ 2 = (d-3) (d + 3)$

Finally, the factored expression is:

$(d ^ 2 + 9) (d-3) (d + 3)$

Answer:

$(d ^ 2 + 9) (d-3) (d + 3)$

4 0

3 years ago

Read 2 more answers

From Midnight to 6 am the temperature rose 8 degrees C. At 6 am the temperature was -21 degrees C. What was the temperature at m

Alika [10]

Hello!

We know that from midnight to 6am the temperature went up 8° and at 6am it was -21°

To find what it was at midnight we have to work backwards

Since it went up we have to subtract 8 from -21

-21 - 8 = -29

The answer is -29°C

Hope this helps!

7 0

2 years ago

Read 2 more answers

If x+y=6 and xy =2find x³+y³(please help me fast with explanation also please) T^T

Maurinko [17]

Answer: x³+y³=180

Step-by-step explain: let's remember the formula x³+y³=(x+y)(x²-xy+y²) and also x³+y³=(x+y)³-3xy(x+y) then $\displaystyle\boldsymbol{ x^3+y^3=\underbrace{(x+y)^3}_{6}-3\underbrace{xy}_{2}\underbrace{(x+y)}_6}=\\\\6^3-3\cdot 2\cdot 6=216-36=180$

6 0

3 years ago