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Crank
3 years ago
14

What is the outlier for the data set?

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0
3.) 9 is the Outlier here.

It is because, natural numbers are listed between 4 to 8, but 9 came first...before 7 that's why it is an Outlier

Hope this helps!
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I had to rewrite the questions cause I don't know how to edit them on a computer and PLEASE ANSWER but here is the question:
Ipatiy [6.2K]

Answer

v=13

Step-by-step explanation:

110/9 = v

Round up.

8 0
3 years ago
Please answer questions 3 and 4 :))
Gnoma [55]
1.) D
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6 0
2 years ago
If 7x - 4y = 23 and x + y = 8, what is the value of x?
Margaret [11]

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

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8 0
3 years ago
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Find the measure of a supplement of a 20 3/4 degrees
ki77a [65]
20 \frac{3}{4}= \frac{83}{4} \\ \\ 180^{(4}-\frac{83}{4}= \frac{720-83}{4}=\boxed{\frac{637}{4}=159 \frac{1}{4}-the \ suplement}
4 0
3 years ago
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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

x=(7)+(-4)t

x=7-4t

Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

5 0
3 years ago
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