Given:
Two vectors are:


To find:
The projection of u onto v.
Solution:
Magnitude of a vector
is:

Dot product of two vector
and
is:

Formula for projection of u onto v is:




On further simplification, we get



Therefore, the projection of u onto v is
.
Answer:
140
Step-by-step explanation:
To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.
First, let's count the number of subsets that contain the element 3.
Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is
.
Now, let's count the number of subsets that contain the element 4.
4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in
ways.
We conclude that there are 70+70=140 required subsets of S.
We know that
a) find <span>the ratio of the perimeters
</span><span>
the ratio of the perimeters is equal to the scale factor
</span>scale factor=26/6-----> 13/3
the answer Part a) is
the ratio of the perimeters is 13/3
b) find <span>the ratio of the areas of the larger figure to the smaller figure
we know that
area larger figure=[scale factor]</span>²*area smaller figure
scale factor²=area larger figure/area smaller figure
the ratio of the areas of the larger figure to the smaller figure is equal to scale factor squared
scale factor²=(13/3)²----> 169/9
the answer Part b) is
169/9
the complete answer is
13/3 and 169/9
A. sqrt 36
bc it becomes 6